3.7.63 \(\int \cos ^5(c+d x) \cot ^2(c+d x) (a+a \sin (c+d x)) \, dx\) [663]

3.7.63.1 Optimal result
3.7.63.2 Mathematica [A] (verified)
3.7.63.3 Rubi [A] (verified)
3.7.63.4 Maple [A] (verified)
3.7.63.5 Fricas [A] (verification not implemented)
3.7.63.6 Sympy [F(-1)]
3.7.63.7 Maxima [A] (verification not implemented)
3.7.63.8 Giac [A] (verification not implemented)
3.7.63.9 Mupad [B] (verification not implemented)

3.7.63.1 Optimal result

Integrand size = 27, antiderivative size = 114 \[ \int \cos ^5(c+d x) \cot ^2(c+d x) (a+a \sin (c+d x)) \, dx=-\frac {a \csc (c+d x)}{d}+\frac {a \log (\sin (c+d x))}{d}-\frac {3 a \sin (c+d x)}{d}-\frac {3 a \sin ^2(c+d x)}{2 d}+\frac {a \sin ^3(c+d x)}{d}+\frac {3 a \sin ^4(c+d x)}{4 d}-\frac {a \sin ^5(c+d x)}{5 d}-\frac {a \sin ^6(c+d x)}{6 d} \]

output
-a*csc(d*x+c)/d+a*ln(sin(d*x+c))/d-3*a*sin(d*x+c)/d-3/2*a*sin(d*x+c)^2/d+a 
*sin(d*x+c)^3/d+3/4*a*sin(d*x+c)^4/d-1/5*a*sin(d*x+c)^5/d-1/6*a*sin(d*x+c) 
^6/d
 
3.7.63.2 Mathematica [A] (verified)

Time = 0.03 (sec) , antiderivative size = 114, normalized size of antiderivative = 1.00 \[ \int \cos ^5(c+d x) \cot ^2(c+d x) (a+a \sin (c+d x)) \, dx=-\frac {a \csc (c+d x)}{d}+\frac {a \log (\sin (c+d x))}{d}-\frac {3 a \sin (c+d x)}{d}-\frac {3 a \sin ^2(c+d x)}{2 d}+\frac {a \sin ^3(c+d x)}{d}+\frac {3 a \sin ^4(c+d x)}{4 d}-\frac {a \sin ^5(c+d x)}{5 d}-\frac {a \sin ^6(c+d x)}{6 d} \]

input
Integrate[Cos[c + d*x]^5*Cot[c + d*x]^2*(a + a*Sin[c + d*x]),x]
 
output
-((a*Csc[c + d*x])/d) + (a*Log[Sin[c + d*x]])/d - (3*a*Sin[c + d*x])/d - ( 
3*a*Sin[c + d*x]^2)/(2*d) + (a*Sin[c + d*x]^3)/d + (3*a*Sin[c + d*x]^4)/(4 
*d) - (a*Sin[c + d*x]^5)/(5*d) - (a*Sin[c + d*x]^6)/(6*d)
 
3.7.63.3 Rubi [A] (verified)

Time = 0.28 (sec) , antiderivative size = 115, normalized size of antiderivative = 1.01, number of steps used = 6, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.185, Rules used = {3042, 3315, 27, 99, 2009}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \cos ^5(c+d x) \cot ^2(c+d x) (a \sin (c+d x)+a) \, dx\)

\(\Big \downarrow \) 3042

\(\displaystyle \int \frac {\cos (c+d x)^7 (a \sin (c+d x)+a)}{\sin (c+d x)^2}dx\)

\(\Big \downarrow \) 3315

\(\displaystyle \frac {\int \csc ^2(c+d x) (a-a \sin (c+d x))^3 (\sin (c+d x) a+a)^4d(a \sin (c+d x))}{a^7 d}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {\int \frac {\csc ^2(c+d x) (a-a \sin (c+d x))^3 (\sin (c+d x) a+a)^4}{a^2}d(a \sin (c+d x))}{a^5 d}\)

\(\Big \downarrow \) 99

\(\displaystyle \frac {\int \left (-\sin ^5(c+d x) a^5-\sin ^4(c+d x) a^5+3 \sin ^3(c+d x) a^5+\csc ^2(c+d x) a^5+3 \sin ^2(c+d x) a^5+\csc (c+d x) a^5-3 \sin (c+d x) a^5-3 a^5\right )d(a \sin (c+d x))}{a^5 d}\)

\(\Big \downarrow \) 2009

\(\displaystyle \frac {-\frac {1}{6} a^6 \sin ^6(c+d x)-\frac {1}{5} a^6 \sin ^5(c+d x)+\frac {3}{4} a^6 \sin ^4(c+d x)+a^6 \sin ^3(c+d x)-\frac {3}{2} a^6 \sin ^2(c+d x)-3 a^6 \sin (c+d x)-a^6 \csc (c+d x)+a^6 \log (a \sin (c+d x))}{a^5 d}\)

input
Int[Cos[c + d*x]^5*Cot[c + d*x]^2*(a + a*Sin[c + d*x]),x]
 
output
(-(a^6*Csc[c + d*x]) + a^6*Log[a*Sin[c + d*x]] - 3*a^6*Sin[c + d*x] - (3*a 
^6*Sin[c + d*x]^2)/2 + a^6*Sin[c + d*x]^3 + (3*a^6*Sin[c + d*x]^4)/4 - (a^ 
6*Sin[c + d*x]^5)/5 - (a^6*Sin[c + d*x]^6)/6)/(a^5*d)
 

3.7.63.3.1 Defintions of rubi rules used

rule 27
Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 99
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_) 
)^(p_), x_] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d*x)^n*(e + f*x)^p, x], 
 x] /; FreeQ[{a, b, c, d, e, f, p}, x] && IntegersQ[m, n] && (IntegerQ[p] | 
| (GtQ[m, 0] && GeQ[n, -1]))
 

rule 2009
Int[u_, x_Symbol] :> Simp[IntSum[u, x], x] /; SumQ[u]
 

rule 3042
Int[u_, x_Symbol] :> Int[DeactivateTrig[u, x], x] /; FunctionOfTrigOfLinear 
Q[u, x]
 

rule 3315
Int[cos[(e_.) + (f_.)*(x_)]^(p_)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_ 
.)*((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)])^(n_.), x_Symbol] :> Simp[1/(b^p* 
f)   Subst[Int[(a + x)^(m + (p - 1)/2)*(a - x)^((p - 1)/2)*(c + (d/b)*x)^n, 
 x], x, b*Sin[e + f*x]], x] /; FreeQ[{a, b, e, f, c, d, m, n}, x] && Intege 
rQ[(p - 1)/2] && EqQ[a^2 - b^2, 0]
 
3.7.63.4 Maple [A] (verified)

Time = 0.33 (sec) , antiderivative size = 105, normalized size of antiderivative = 0.92

method result size
derivativedivides \(\frac {a \left (\frac {\left (\cos ^{6}\left (d x +c \right )\right )}{6}+\frac {\left (\cos ^{4}\left (d x +c \right )\right )}{4}+\frac {\left (\cos ^{2}\left (d x +c \right )\right )}{2}+\ln \left (\sin \left (d x +c \right )\right )\right )+a \left (-\frac {\cos ^{8}\left (d x +c \right )}{\sin \left (d x +c \right )}-\left (\frac {16}{5}+\cos ^{6}\left (d x +c \right )+\frac {6 \left (\cos ^{4}\left (d x +c \right )\right )}{5}+\frac {8 \left (\cos ^{2}\left (d x +c \right )\right )}{5}\right ) \sin \left (d x +c \right )\right )}{d}\) \(105\)
default \(\frac {a \left (\frac {\left (\cos ^{6}\left (d x +c \right )\right )}{6}+\frac {\left (\cos ^{4}\left (d x +c \right )\right )}{4}+\frac {\left (\cos ^{2}\left (d x +c \right )\right )}{2}+\ln \left (\sin \left (d x +c \right )\right )\right )+a \left (-\frac {\cos ^{8}\left (d x +c \right )}{\sin \left (d x +c \right )}-\left (\frac {16}{5}+\cos ^{6}\left (d x +c \right )+\frac {6 \left (\cos ^{4}\left (d x +c \right )\right )}{5}+\frac {8 \left (\cos ^{2}\left (d x +c \right )\right )}{5}\right ) \sin \left (d x +c \right )\right )}{d}\) \(105\)
parallelrisch \(\frac {\left (-100-192 \ln \left (\sec ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+\frac {12 \left (-206+222 \cos \left (d x +c \right )-32 \cos \left (2 d x +2 c \right )+17 \cos \left (3 d x +3 c \right )-2 \cos \left (4 d x +4 c \right )+\cos \left (5 d x +5 c \right )\right ) \cot \left (\frac {d x}{2}+\frac {c}{2}\right )}{5}-96 \sec \left (\frac {d x}{2}+\frac {c}{2}\right ) \csc \left (\frac {d x}{2}+\frac {c}{2}\right )+\cos \left (6 d x +6 c \right )+192 \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )+87 \cos \left (2 d x +2 c \right )+12 \cos \left (4 d x +4 c \right )\right ) a}{192 d}\) \(149\)
risch \(\frac {19 i a \,{\mathrm e}^{i \left (d x +c \right )}}{16 d}-i a x -\frac {2 i a c}{d}+\frac {29 a \,{\mathrm e}^{2 i \left (d x +c \right )}}{128 d}-\frac {2 i a \,{\mathrm e}^{i \left (d x +c \right )}}{d \left ({\mathrm e}^{2 i \left (d x +c \right )}-1\right )}-\frac {19 i a \,{\mathrm e}^{-i \left (d x +c \right )}}{16 d}+\frac {29 a \,{\mathrm e}^{-2 i \left (d x +c \right )}}{128 d}+\frac {a \ln \left ({\mathrm e}^{2 i \left (d x +c \right )}-1\right )}{d}+\frac {a \cos \left (6 d x +6 c \right )}{192 d}-\frac {a \sin \left (5 d x +5 c \right )}{80 d}+\frac {a \cos \left (4 d x +4 c \right )}{16 d}-\frac {3 a \sin \left (3 d x +3 c \right )}{16 d}\) \(183\)
norman \(\frac {-\frac {a}{2 d}-\frac {19 a \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{2 d}-\frac {65 a \left (\tan ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{2 d}-\frac {599 a \left (\tan ^{6}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{10 d}-\frac {599 a \left (\tan ^{8}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{10 d}-\frac {65 a \left (\tan ^{10}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{2 d}-\frac {19 a \left (\tan ^{12}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{2 d}-\frac {a \left (\tan ^{14}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{2 d}-\frac {68 a \left (\tan ^{7}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{3 d}-\frac {12 a \left (\tan ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d}-\frac {12 a \left (\tan ^{9}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d}-\frac {6 a \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d}-\frac {6 a \left (\tan ^{11}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d}}{\left (1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )^{6} \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}+\frac {a \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d}-\frac {a \ln \left (1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d}\) \(275\)

input
int(cos(d*x+c)^7*csc(d*x+c)^2*(a+a*sin(d*x+c)),x,method=_RETURNVERBOSE)
 
output
1/d*(a*(1/6*cos(d*x+c)^6+1/4*cos(d*x+c)^4+1/2*cos(d*x+c)^2+ln(sin(d*x+c))) 
+a*(-1/sin(d*x+c)*cos(d*x+c)^8-(16/5+cos(d*x+c)^6+6/5*cos(d*x+c)^4+8/5*cos 
(d*x+c)^2)*sin(d*x+c)))
 
3.7.63.5 Fricas [A] (verification not implemented)

Time = 0.28 (sec) , antiderivative size = 113, normalized size of antiderivative = 0.99 \[ \int \cos ^5(c+d x) \cot ^2(c+d x) (a+a \sin (c+d x)) \, dx=\frac {48 \, a \cos \left (d x + c\right )^{6} + 96 \, a \cos \left (d x + c\right )^{4} + 384 \, a \cos \left (d x + c\right )^{2} + 240 \, a \log \left (\frac {1}{2} \, \sin \left (d x + c\right )\right ) \sin \left (d x + c\right ) + 5 \, {\left (8 \, a \cos \left (d x + c\right )^{6} + 12 \, a \cos \left (d x + c\right )^{4} + 24 \, a \cos \left (d x + c\right )^{2} - 19 \, a\right )} \sin \left (d x + c\right ) - 768 \, a}{240 \, d \sin \left (d x + c\right )} \]

input
integrate(cos(d*x+c)^7*csc(d*x+c)^2*(a+a*sin(d*x+c)),x, algorithm="fricas" 
)
 
output
1/240*(48*a*cos(d*x + c)^6 + 96*a*cos(d*x + c)^4 + 384*a*cos(d*x + c)^2 + 
240*a*log(1/2*sin(d*x + c))*sin(d*x + c) + 5*(8*a*cos(d*x + c)^6 + 12*a*co 
s(d*x + c)^4 + 24*a*cos(d*x + c)^2 - 19*a)*sin(d*x + c) - 768*a)/(d*sin(d* 
x + c))
 
3.7.63.6 Sympy [F(-1)]

Timed out. \[ \int \cos ^5(c+d x) \cot ^2(c+d x) (a+a \sin (c+d x)) \, dx=\text {Timed out} \]

input
integrate(cos(d*x+c)**7*csc(d*x+c)**2*(a+a*sin(d*x+c)),x)
 
output
Timed out
 
3.7.63.7 Maxima [A] (verification not implemented)

Time = 0.20 (sec) , antiderivative size = 91, normalized size of antiderivative = 0.80 \[ \int \cos ^5(c+d x) \cot ^2(c+d x) (a+a \sin (c+d x)) \, dx=-\frac {10 \, a \sin \left (d x + c\right )^{6} + 12 \, a \sin \left (d x + c\right )^{5} - 45 \, a \sin \left (d x + c\right )^{4} - 60 \, a \sin \left (d x + c\right )^{3} + 90 \, a \sin \left (d x + c\right )^{2} - 60 \, a \log \left (\sin \left (d x + c\right )\right ) + 180 \, a \sin \left (d x + c\right ) + \frac {60 \, a}{\sin \left (d x + c\right )}}{60 \, d} \]

input
integrate(cos(d*x+c)^7*csc(d*x+c)^2*(a+a*sin(d*x+c)),x, algorithm="maxima" 
)
 
output
-1/60*(10*a*sin(d*x + c)^6 + 12*a*sin(d*x + c)^5 - 45*a*sin(d*x + c)^4 - 6 
0*a*sin(d*x + c)^3 + 90*a*sin(d*x + c)^2 - 60*a*log(sin(d*x + c)) + 180*a* 
sin(d*x + c) + 60*a/sin(d*x + c))/d
 
3.7.63.8 Giac [A] (verification not implemented)

Time = 0.34 (sec) , antiderivative size = 101, normalized size of antiderivative = 0.89 \[ \int \cos ^5(c+d x) \cot ^2(c+d x) (a+a \sin (c+d x)) \, dx=-\frac {10 \, a \sin \left (d x + c\right )^{6} + 12 \, a \sin \left (d x + c\right )^{5} - 45 \, a \sin \left (d x + c\right )^{4} - 60 \, a \sin \left (d x + c\right )^{3} + 90 \, a \sin \left (d x + c\right )^{2} - 60 \, a \log \left ({\left | \sin \left (d x + c\right ) \right |}\right ) + 180 \, a \sin \left (d x + c\right ) + \frac {60 \, {\left (a \sin \left (d x + c\right ) + a\right )}}{\sin \left (d x + c\right )}}{60 \, d} \]

input
integrate(cos(d*x+c)^7*csc(d*x+c)^2*(a+a*sin(d*x+c)),x, algorithm="giac")
 
output
-1/60*(10*a*sin(d*x + c)^6 + 12*a*sin(d*x + c)^5 - 45*a*sin(d*x + c)^4 - 6 
0*a*sin(d*x + c)^3 + 90*a*sin(d*x + c)^2 - 60*a*log(abs(sin(d*x + c))) + 1 
80*a*sin(d*x + c) + 60*(a*sin(d*x + c) + a)/sin(d*x + c))/d
 
3.7.63.9 Mupad [B] (verification not implemented)

Time = 11.17 (sec) , antiderivative size = 340, normalized size of antiderivative = 2.98 \[ \int \cos ^5(c+d x) \cot ^2(c+d x) (a+a \sin (c+d x)) \, dx=\frac {a\,\ln \left (\frac {\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )}{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}\right )}{d}-\frac {a\,\ln \left (\frac {1}{{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2}\right )}{d}-\frac {6\,a\,{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2}{d}+\frac {18\,a\,{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4}{d}-\frac {104\,a\,{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^6}{3\,d}+\frac {44\,a\,{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^8}{d}-\frac {32\,a\,{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{10}}{d}+\frac {32\,a\,{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{12}}{3\,d}-\frac {13\,a\,\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}{2\,d\,\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )}-\frac {a\,\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )}{2\,d\,\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}+\frac {14\,a\,{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3}{d\,\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )}-\frac {112\,a\,{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^5}{5\,d\,\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )}+\frac {136\,a\,{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^7}{5\,d\,\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )}-\frac {96\,a\,{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^9}{5\,d\,\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )}+\frac {32\,a\,{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{11}}{5\,d\,\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )} \]

input
int((cos(c + d*x)^7*(a + a*sin(c + d*x)))/sin(c + d*x)^2,x)
 
output
(a*log(sin(c/2 + (d*x)/2)/cos(c/2 + (d*x)/2)))/d - (a*log(1/cos(c/2 + (d*x 
)/2)^2))/d - (6*a*cos(c/2 + (d*x)/2)^2)/d + (18*a*cos(c/2 + (d*x)/2)^4)/d 
- (104*a*cos(c/2 + (d*x)/2)^6)/(3*d) + (44*a*cos(c/2 + (d*x)/2)^8)/d - (32 
*a*cos(c/2 + (d*x)/2)^10)/d + (32*a*cos(c/2 + (d*x)/2)^12)/(3*d) - (13*a*c 
os(c/2 + (d*x)/2))/(2*d*sin(c/2 + (d*x)/2)) - (a*sin(c/2 + (d*x)/2))/(2*d* 
cos(c/2 + (d*x)/2)) + (14*a*cos(c/2 + (d*x)/2)^3)/(d*sin(c/2 + (d*x)/2)) - 
 (112*a*cos(c/2 + (d*x)/2)^5)/(5*d*sin(c/2 + (d*x)/2)) + (136*a*cos(c/2 + 
(d*x)/2)^7)/(5*d*sin(c/2 + (d*x)/2)) - (96*a*cos(c/2 + (d*x)/2)^9)/(5*d*si 
n(c/2 + (d*x)/2)) + (32*a*cos(c/2 + (d*x)/2)^11)/(5*d*sin(c/2 + (d*x)/2))